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Abhidnya Foundations
Clear Concepts, Bright Future
🚀 Physics · Kinematics

Motion & Rest

Everything you need at a glance — concepts, formulas, graphs, equations of motion, free fall, real-world connections, and "Did You Know" facts. Covers Class 9 through JEE level.

Class 9 NCERT JEE Dropper Equations of Motion Graphs Free Fall Circular Motion
Study Level:
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Core Concepts
Master the foundations — rest, motion, distance, displacement, speed, velocity, and acceleration.
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Rest

An object is said to be at rest when its position does not change with time with respect to a reference point. Rest and motion are relative — an object can be at rest for one observer and in motion for another.

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Motion

An object is in motion when its position changes with time in the frame of reference of the observer. Motion can be uniform or non-uniform, along a straight line or curved path.

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Distance

The total length of the path covered by an object in a given time interval. It is a scalar quantity — only magnitude, no direction. Distance is always positive or zero, never negative.

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Displacement

The shortest distance from the initial to the final position of an object. It is a vector quantity — has both magnitude and direction. Displacement can be positive, negative, or zero.

Speed

The distance covered per unit time. It is a scalar quantity. Average speed = total distance ÷ total time. Speed is always positive. SI unit: m/s.

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Velocity

Speed with direction. Displacement covered per unit time. It is a vector quantity. Velocity can be positive, negative, or zero. Average velocity = total displacement ÷ total time.

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Acceleration

The rate of change of velocity. a = (v − u) / t. Positive if velocity increases; negative (retardation/deceleration) if velocity decreases. SI unit: m/s². It is a vector quantity.

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Uniform Motion

An object covers equal distances in equal time intervals. Velocity is constant. Acceleration is zero. Distance-time graph is a straight line.

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Non-Uniform Motion

An object covers unequal distances in equal time intervals. Velocity changes. Acceleration may be constant or variable. A car in city traffic is a typical example.

Distance vs Displacement — Key Comparison

O C (25km) B (35km) A (60km) Path O→A: Distance = 60 km Path A→C: Distance = 35 km Displacement O→C = 25 km → Total Distance (O→A→C) = 95 km Displacement (O→C) = 25 km Distance ≥ |Displacement| always!
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Real-World Connection — Odometer vs GPS

Your car's odometer measures distance — it adds up every metre of road covered, including all turns and detours. A GPS showing straight-line distance from start to end measures displacement. On a winding mountain road, the odometer may show 150 km while GPS displacement is only 80 km — this gap is distance vs displacement in real life!

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Did You Know? — Everything is Relative!

There is no such thing as absolute rest or absolute motion. The passengers in a moving train are at rest relative to each other, but in motion relative to someone standing outside. Even the "stationary" ground beneath your feet is moving — Earth rotates at ~1,670 km/h and orbits the Sun at ~107,000 km/h. Rest and motion only make sense when you specify relative to what.

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JEE Level — Advanced Concepts

These go beyond Class 9 to include vector treatment, instantaneous quantities, variable acceleration, and advanced problem-solving tools needed for JEE.

Instantaneous Velocity JEE

The velocity at a specific instant: v = dx/dt (derivative of position with respect to time). The slope of the tangent to the position-time graph at any point gives instantaneous velocity. The word "velocity" alone implies instantaneous velocity.

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Instantaneous Speed JEE

The magnitude of instantaneous velocity: v = |dx/dt| = ds/dt. The slope of the distance-time (not displacement-time) graph gives instantaneous speed. Instantaneous speed is always ≥ 0.

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Instantaneous Acceleration JEE

a = dv/dt = d²x/dt². The slope of the tangent to the v-t graph at any point. Also equals the second derivative of position w.r.t. time. Acceleration can be non-zero even when velocity is zero (ball at peak).

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Variable Acceleration JEE

When acceleration depends on time, position, or velocity, standard equations (v=u+at) don't apply. Use integration: v = u + ∫a(t)dt or the chain rule: a = v·dv/dx for position-dependent acceleration.

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Average vs Instantaneous JEE

Average speed = total distance/total time. Average velocity = total displacement/total time. These are not equal unless object moves in one direction only. For uniform motion, instantaneous = average velocity = instantaneous speed.

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Relative Motion JEE

Velocity of A relative to B: v_AB = v_A − v_B. Key for problems involving two moving objects — trains approaching/separating, swimmer in river, etc. Always define positive direction carefully.

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JEE Key Result — Average Speed Special Cases

• If a particle travels equal distances at speeds v₁ and v₂: average speed = 2v₁v₂/(v₁+v₂) (harmonic mean)
• If a particle travels equal time intervals at speeds v₁ and v₂: average speed = (v₁+v₂)/2 (arithmetic mean)
• Average speed can never be zero (unless at rest throughout). Average velocity can be zero even if average speed ≠ 0.

Motion Graphs
Reading graphs is one of the most tested skills — in school exams and JEE both.
Distance-Time (s–t) Graph
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Object at REST
Horizontal line

A line parallel to the time-axis. Distance doesn't change → object is not moving. Slope = 0 → speed = 0.

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UNIFORM Speed
Straight inclined line

A straight line with positive slope. Equal distances in equal times. Slope = constant speed. Steeper line = faster speed.

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NON-Uniform Speed
Curved line

A curved (non-linear) line. Slope changes → speed is changing. Steepening curve = acceleration; flattening = deceleration.

Velocity-Time (v–t) Graph
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Constant Velocity
Horizontal line

Parallel to x-axis. Acceleration = 0. The area under this line = distance = velocity × time (a rectangle).

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Uniform Acceleration
Straight inclined line

Straight line with positive slope. Slope = constant acceleration. Area under graph = displacement. Area of triangle + rectangle.

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Uniform Deceleration
Downward sloping line

Straight line with negative slope. Velocity decreasing. Object is retarding. If it reaches zero, object has stopped.

📌 Golden Rules for Graph Reading
s–t graph slope
→ gives speed/velocity
v–t graph slope
→ gives acceleration
v–t graph area
→ gives displacement
s–t vertical line
→ impossible (infinite speed)
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Did You Know? — Train Timetables and s-t Graphs

The distance-time graph of a train between stations looks like a trapezoid: starting from rest (gradual slope), moving at constant speed (steep straight line), then decelerating to stop (decreasing slope). Railway engineers use these graphs to ensure safe acceleration and braking profiles. A vertical line on the graph would mean teleportation — instantaneous travel — which is physically impossible!

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JEE Graph Mastery

Beyond basic reading — JEE tests ability to construct graphs, read slopes of tangents, compute areas of irregular shapes, and interpret non-standard graphs like a–x, v–x, and a–v plots.

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a–t Graph Area JEE
Integration

Area under the a–t graph = change in velocity (Δv). If a is constant: Δv = a × t. For variable acceleration, integrate: Δv = ∫a dt. This is the fundamental link between a-t and v-t graphs.

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v–x Graph (Velocity vs Position) JEE
Chain rule

Used when acceleration depends on position. Use: a = v·dv/dx. The slope of v–x graph multiplied by v gives acceleration. Area under v–x graph has no standard physical meaning unless specified.

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Non-uniform s–t Graph JEE
Tangent slope

Instantaneous velocity at any point = slope of tangent drawn to the s–t curve at that point. Retardation: curve bends toward time-axis (slope decreasing). Acceleration: curve bends away (slope increasing).

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v = b√x (Special Case) JEE
Constant a

If v = b√x, then a = v·dv/dx = b√x · (b/2√x) = b²/2. This is constant acceleration! v² = b²x is a straight line on the v²–x graph, confirming constant acceleration.

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JEE Trap — Displacement vs Distance from v–t Graph

The area under the v–t graph gives displacement (net, with sign). To find distance, you must separate regions where v is positive and negative, take absolute values of each area, and add them. If a v–t graph crosses the time axis, the areas above and below axis correspond to motion in opposite directions — don't add them directly for distance!

Equations of Motion
Three fundamental equations relating displacement, velocity, acceleration, and time.
Velocity–Time Relation (1st Equation)

Final velocity after uniform acceleration

v = u + at
v = final velocity (m/s) u = initial velocity (m/s) a = acceleration (m/s²) t = time (s)
a = (v−u) / t
t = (v−u) / a
u = v − at
Does not involve displacement (s). Use this when you know or need velocity and time.
Position–Time Relation (2nd Equation)

Displacement during uniform acceleration

s = ut + ½at²
s = displacement (m) u = initial velocity (m/s) a = acceleration (m/s²) t = time (s)
Does not involve final velocity (v). Use when you know time and want distance. If u = 0: s = ½at².
Velocity–Position Relation (3rd Equation)

Velocity after covering a displacement

v² = u² + 2as
v = final velocity (m/s) u = initial velocity (m/s) a = acceleration (m/s²) s = displacement (m)
s = (v²−u²) / 2a
a = (v²−u²) / 2s
Does not involve time (t). Use when time is not given or needed. Perfect for "find the stopping distance" problems.
Average Velocity (Uniform Acceleration)

Shortcut for displacement

v_avg = (u + v) / 2  and  s = v_avg × t
Only valid when acceleration is constant. The average of initial and final velocity gives the average velocity.
Uniform Circular Motion

Speed in circular motion

v = 2πr / T
v = speed (m/s) r = radius (m) T = time period (s)
Even though speed is constant in uniform circular motion, the direction changes continuously — so the object is accelerating!

Which Equation to Use? — Quick Decision Guide

Know v, u, t — need a or s? → 1st equation (v = u + at) or 2nd (s = ut + ½at²)
No final velocity given? → Use 2nd equation (s = ut + ½at²)
No time given? → Use 3rd equation (v² = u² + 2as)
Object starts from rest? → Set u = 0 in all equations

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JEE Additional Formulas

These extend the basic three equations for more complex situations tested at JEE level.

Displacement in nth Second JEE

Distance covered in the n-th second only

Sₙ = u + a/2 × (2n − 1)
Sₙ = displacement in nth second (m) u = initial velocity (m/s) a = acceleration (m/s²) n = the nth second
Derived from: Sₙ = s(t=n) − s(t=n−1). Note: Sₙ is displacement in the nth second, NOT in n seconds total.
Variable Acceleration — Integration JEE

When a depends on t, x, or v

v = u + ∫a(t)dt  |  v·dv/dx = a(x)
For a(t): integrate directly. For a(x): use chain rule v·dv/dx = a(x) and separate variables. For a(v): separate dv/a(v) = dt and integrate.
Free Fall Under Gravity JEE

For a body thrown upward with velocity u

H_max = u²/2g  |  T = 2u/g  |  t_ascent = t_descent = u/g
H_max = maximum height T = total time of flight g = 9.8 m/s² (≈10 m/s²)
Galileo's Law of Odd Numbers: distances covered in 1st, 2nd, 3rd... seconds from rest are in ratio 1:3:5:... Total distances in 1s, 2s, 3s... are in ratio 1:4:9...
Units & Constants
Every physical quantity, its unit, symbol, and important values.
Quantity Symbol SI Unit Type Key Formula / Notes
Position / Displacement s, x m (metre) Vector Displacement = final − initial position. Can be +ve, −ve, or zero.
Distance d m (metre) Scalar Total path length. Always ≥ |displacement|. Always positive.
Speed v m/s Scalar v = d/t. Also expressed as km/h. 1 km/h = 5/18 m/s. 1 m/s = 18/5 km/h.
Velocity v m/s Vector v = displacement/time. Can be +ve, −ve, or zero. Direction matters!
Acceleration a m/s² Vector a = (v−u)/t. Negative a = deceleration. CGS unit: cm/s². Dimension: [M⁰L¹T⁻²]
Time t s (second) Scalar Always positive in kinematic problems. Dimension: [T].
Gravitational acceleration (g) g m/s² Vector g = 9.8 m/s² (precise) or 10 m/s² (problems). Directed downward always.
Angular Velocity ω rad/s Vector For circular motion: v = rω. ω = 2π/T = 2πf.
Important Values & Conversion Facts
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Unit Conversion1 km/h = 5/18 m/s ≈ 0.278 m/s
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Unit Conversion1 m/s = 18/5 km/h = 3.6 km/h
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g on Earth9.8 m/s² (exact), 10 m/s² (problems)
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g on Moon~1.6 m/s² (about 1/6th of Earth)
Speed of light3 × 10⁸ m/s — fastest in universe
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Speed of sound (air)~346 m/s at room temperature
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City speed limit50 km/h ≈ 13.9 m/s
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Typical aircraft speed900 km/h ≈ 250 m/s
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Usain Bolt (100m record)~10.44 m/s average; peak ~12.4 m/s
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Earth's orbital speed~30 km/s = 30,000 m/s around Sun
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Did You Know? — The 5/18 Trick

Converting km/h to m/s: multiply by 5/18. Converting m/s to km/h: multiply by 18/5 = 3.6. Why? Because 1 km = 1000 m and 1 hour = 3600 s, so 1 km/h = 1000/3600 = 5/18 m/s. This conversion is needed in almost every motion problem — memorise it as a reflex! Quick check: 72 km/h = 72 × (5/18) = 20 m/s.

Real-Life Connections
Motion is everywhere — recognise it, relate it, understand it.
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Did You Know? — Galileo's Ramp Experiment

Galileo couldn't measure free fall directly (too fast for 16th century timing). So he slowed it down by rolling balls down inclined planes and proved that distance is proportional to t² — the same relationship as free fall, just scaled. He then extrapolated to 90° (vertical) to derive g. His experiment with the Leaning Tower of Pisa (dropping two cannonballs) showed mass doesn't affect acceleration — overturning 2000 years of Aristotelian physics in one afternoon.

Key Notes, Assumptions & Common Mistakes
What to always remember — and what traps to avoid in exams.

✅ Air Resistance Ignored

Unless stated, all free fall problems assume no air resistance. In reality, a feather falls slower than a stone — but in a vacuum they fall at the same rate. This is a standard simplifying assumption.

✅ Equations Valid Only for Constant a

The three equations of motion (v=u+at, s=ut+½at², v²=u²+2as) are only valid when acceleration is constant. For variable acceleration, they cannot be used directly.

✅ g is Approximately Constant

Near Earth's surface, g ≈ 9.8 m/s² and is treated as constant. For very large heights, g decreases with altitude. School problems use 10 m/s² for simplicity.

⚠️ Distance ≠ Displacement

The most common mistake: using distance in velocity formula (should be displacement) or vice versa. Average speed uses total distance; average velocity uses net displacement.

⚠️ Speed ≠ Velocity

Speed is scalar (only magnitude), velocity is vector (magnitude + direction). A car going around a circular track at constant speed still has changing velocity because direction changes.

⚠️ v=0 Does Not Mean a=0

A ball thrown upward has v=0 at the highest point but a = −g = −9.8 m/s² (or −10 m/s²) at that point. The acceleration due to gravity never becomes zero just because velocity does.

📌 Sign Convention is Key

Always define a positive direction first! Upward = +ve usually. Then g = −10 m/s² (acts downward). Consistency is everything — a wrong sign flips your entire answer.

📌 Uniform Circular Motion

Speed is constant, but velocity is not — direction keeps changing. Therefore the object IS accelerating (centripetally, toward the centre), even though its speed is constant.

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JEE Advanced Notes

Additional precision and traps specific to JEE-level problems.

JEE Trap — Sₙ Formula JEE

Sₙ = u + a/2(2n−1) gives displacement in the nth second. It's NOT Sₙ = u·n + ½a·n² (which gives total displacement in n seconds). Very common mistake in MCQs.

Avg Speed ≥ |Avg Velocity| JEE

Always true: average speed ≥ |average velocity|. They are equal only when object moves in one direction without reversing. If direction reverses: distance > |displacement| → speed > |velocity|.

Instantaneous Speed = |Instantaneous Velocity| JEE

At any instant, instantaneous speed = magnitude of instantaneous velocity. This is NOT true for averages. Keep this clearly separate in your mind.

Galileo's Odd Number Ratios JEE

Body from rest with constant a: distances in 1st, 2nd, 3rd... seconds are in ratio 1:3:5:7... (odd numbers). Total distances in 1s, 2s, 3s... are 1:4:9:16... (squares). Frequently tested in multiple-correct JEE questions.

Free Fall: Ascent = Descent Time JEE

Time of ascent = time of descent = u/g (if no air resistance). Speed at projection = speed on return. Total time T = 2u/g. The body is symmetric in time — a key property used in many problems.

Retardation Sign Trap JEE

Retardation is deceleration, meaning acceleration is opposite to velocity. If object moves in +ve direction and decelerates, a is negative. Don't confuse "retardation of 5 m/s²" with "a = +5" — it means a = −5 m/s² in that direction.

Motion Calculators
Instant solutions for kinematic problems. Enter known values and calculate the unknown.

🏃 1st Equation: v = u + at

Enter any three values to find the fourth.

📏 2nd Equation: s = ut + ½at²

Enter any three values to find the fourth.

⚡ 3rd Equation: v² = u² + 2as

Enter any three values to find the fourth (time-independent).

🌍 Free Fall / Projectile Up

Calculate max height, time of flight, or velocity at any point.

🔄 Uniform Circular Motion

Find speed, radius, or time period from v = 2πr/T.
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Try These Classic Problems!

P1 (Braking car): Car at 72 km/h (= 20 m/s) brakes with a = −5 m/s². Stopping distance? → Use 3rd Eq: s = (0² − 20²) / (2×−5) = 40 m
P2 (Free fall): Ball dropped from 20 m. Time to hit ground? → s=½gt²: 20=½×10×t² → t = 2 s, v = gt = 20 m/s
P3 (Train): Starts from rest, reaches 20 m/s in 5 min (300 s). Acceleration? → a = (20−0)/300 = 1/15 m/s²